The correct answer is ** 144 KJ** .

**Work power**, or simply power, is referred to as a physical notion that, depending on the situation and the information at hand, may have a variety of interpretations. The rate of performing labour is referred to as power. Power is defined as the amount of energy used per unit of time. Since it lacks a direction, it is present in scalar amount. Joules/second, or Watt in the SI system, is the unit of power. A watt is the amount of energy required to perform one joule of work in a second.

P = 120 Watts of power

20 minutes plus 60 seconds equals 1200 seconds.

taken t and Energy E= Power P x Time t.

= Work W (or Energy E)/Time

since we know that Power P

Energy** E= 120 W x 1200 = 144000 J or 144 KJ **

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Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting.

T=3.12 Sec

**Distance** d= 9.703m

The **distance** can refer to a physical length in physics or to an estimate based on other factors in ordinary language (e.g. "two counties over"). It is sometimes used to indicate the **distance** between two points: display style |AB||AB|. The terms "distance from A to B" and "**distance** from B to A" are frequently used interchangeably.

It is a generalization of the idea of physical **distance**. **Distance** is a non-numerical measurement in psychology and the social sciences; psychological **distance **refers to how an object feels.

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A stunt man drops from a building and falls 15m down onto a giant air mattress

sketch

A) How much time does it take for the stunt man to hit the air mattress?

B) What is his velocity as he slams into the mattress (# and direction)?

PLEASE HELP!!! ASAP

A. The **time taken** for the stunt man to hit the mattress is **1.75 s**

B. The **velocity** the stunt man as he slams into the mattress is **17.15 m/s**

h = ½gt²

15 = ½ × 9.8 × t²

15 = 4.9 × t²

Divide both side by 4.9

t² = 15 / 4.9

Take the square root of both side

t = √(15 / 4.9)

**t = ****1****.****7****5**** s**

Thus, it will take the stunt man **1.75 s** to hit the mattress

v = gt

v = 9.8 × 1.75

**v**** ****=**** ****1****7****.****1****5**** ****m****/****s**

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What is the average velocity of a car that travels 12 kilometers in 0.20 hours?

**Answer:**

60 km/hr

**Explanation:**

Looking for km / hr

12 km / (.20 hr) = 60 km/hr

A crane is used to raise one end of a steel girder off the ground, as shown in Figure 14. When the cable attached to the end of the girder is at 20° to the vertical, the force of the cable on the girder is 6.5 kN. Calculate the horizontal and vertical components of this force. Brider 20% 6.5 KN

The **horizontal component** of the force of cable is 2.22 kN. The **vertical component** of the force of cable is 6.1 kN.

If we draw a free body diagram of the force of the cable with its horizontal and vertical components, it will form a right angled triangle.

**sin θ = Opposite side / Hypotenuse**

**cos θ = Adjacent side / Hypotenuse**

θ = 20°

Hypotenuse = Force of cable = 6.5 kN

Opposite side = Horizontal component

Adjacent side = Vertical component

sin 20° = Horizontal component / 6.5

Horizontal component = 0.342 * 6.5

Horizontal component = 2.22 kN

cos 20° = Vertical component / 6.5

Vertical component = 6.1 kN

In a **right angled triangle**, trigonometric ratios can be used as mentioned below.

Therefore,

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< Question 11 of 27 >

A car traveling 88.0 km/h on a straight road is 2500 m behind a truck traveling at 64.0 km/h.

How much time t will it take the car to catch up with the truck?

t =

A truck moving at 64.0 km/h is 2500 m behind an automobile traveling at 88.0 km/h on a straight route.

How long will it take the automobile to overtake the truck?

**Distance** is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

**41 kilometers**

After a half-hour, the first car is 32.5 kilometers to the north. After a half-hour, the second automobile is 25 kilometers east. You can find out their angular separation from one another using the **Pythagorean theorem**:

d = √(32.5² +25²) = √1681.25 ≈ 41.00

After a half-hour, the automobiles are around 41 kilometers apart.

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Hello what is U ? [tex]V=\frac{U}{q}[/tex]

I think that is potential energy

S.I unit for moment of inertia of a fly wheel

**Answer:**

m is expressed in kilograms and r in metres, with I (moment of inertia) having the dimension kilogram-metre square.

Chance drives her scooter 7 km north. She stops for lunch and then drives 5 km east. She spends 2 hours total. What her distance? displacement? average speed? average velocity?

Distance - **12 Km**Displacement - **8.6 km East of North**Average velocity - **4.3Km/hr East of North**Average speed - ** 6 Km/hr**What is the distance?

We know that the **distance **is the **difference **between two points. The distance covered is a **scalar quantity **hence we can obtain the total speed **algebraically**. The displacement is a** vector quantity** hence we must obtain it **geometrically**.

Total distance = 7 km + 5 km = 12 km

Total displacement = √7^2 + 5^2 = 8.6 km East of North

Average speed = 12 km/ 2 hours = 6 Km/hr

Average velocity = 8.6 km East of North/2 hours = **4.3Km/hr East of North**

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phys 181 check picture

**Answer:**

see below

**Explanation:**

a^3 = 125 m^3

b^2 = 8.41 s^2

c = 45 m/s Plug these values into the equation

125 / ( 8.41 * 45) = **.33 m^2 / s**

A float starts 9.2 m west of a grand stand ( the origin ) for the parade . It heads towards the grandstand at the rate of 1.5m/s . Where is the float located at 3.5s?

The float is **3.95 m** **west** of the grandstand after **3.5** **s** of its start.

The distance is defined as the **total length** of the path taken by a moving body in order to reach the **final position** starting from** initial position. **Mathematically -

Distance **[d]** = Speed** [s]** x time **[t]**

Given that a float starts from **9.2 m** west of a grand stand for the parade with the speed of **1.5 m/s**. Therefore we can write -

Speed** [s] **= 1.5 m/s

Distance between float and grandstand **[D]** = 9.2 m

The location of the float after **3.5 seconds** of its start is as follows-

**d = s x t**

d = 1.5 x 3.5

d = 5.25

Therefore -

Distance between the **float** and the **grandstand **after 3.5 seconds of its start = **D - d** = 9.20 - 5.25 = 3.95 m

Therefore, the float is **3.95 m** **west** of the grandstand after **3.5** **s** of its start.

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Hypersonic scramjet. On March 27, 2004, the United States

successfully tested the hypersonic X-43A scramjet, which flew at

Mach 7 (seven times the speed of sound) for 11 seconds. (b) How many kilometers

did the scramjet travel during its 11 second test?

**25.487 km **did the** scramjet **travel during its 11 second test.

Given that the scramjet travels at a speed seven times that of **sound, speed **v is equal to 7 x 331 m/s or 2317 m/s.

(A) We require the scramjet's travel time over a distance of

d = 5000 km (5x10^6 m).

Using the formula

** time taken = distance traveled/speed, **

we can calculate the following:

(5x10^6)/2317 sec

= (5x10^6)/(23175x60) minute

= 5000000/139020 minutes

= 35.97 seconds

As 1 second equals 1/60 of a minute, Therefore, the travel time on Scramjet from San Francisco to New York will be 35.97 minutes.

(B) The distance covered by the **Scramjet** in 11 seconds must now be determined. as a result,

using speed, distance, and time relation.

**Distance** = Speed x Time

= 7 x 331 x 11

= 25487 m

Since 1 metre equals 1/1000 of a kilometer, 25487 m of **25.487 km**

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In a biathalon race you first ride a bicycle at an average speed of 19.1 mi/h for 18.5 miles, then you must run for another 5.5 miles. With what average speed, in miles per hour, must you run if your average speed for the entire race is to be 14.5 mi/h?

The **average speed** you must run is **7.97 mph**.

The **average speed** of an object is the ratio of total distance traveled by the object to

Average speed = total distance / total time of motion

Total time of motion = total distance / average speed

total time = (18.5 + 5.5) / (14.5)

total time = 1.66 hours

time taken during the bicycle ridet1 = 18.5 / 19.1

t1 = 0.97 hour

time taken during the runt2 = 1.66 hr - 0.97 hr

t2 = 0.69 hr

Average speed during the runv = 5.5 miles /0.69 hr

v = 7.97 mph

Thus, the **average speed** you must run is **7.97 mph.**

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Q1]. An electric field has a magnitude of 400 N/C and makes an angle

60

o

with the perpendicular to the surface of a flat surface of dimensions 30 cm by 20 cm. Calculate the electric flux through the surface.

Q2. Two large horizontal, parallel metal plates are 2.0 cm apart in air and the upper plate is maintained at a positive potential relative to the lower plate so that field strength between them is

2.5x10^5 vm^1.

An electron is released from rest at the lower plate. What is its speed on reaching the upper plate? [e=1.6x10^19 ;me=9.1x10^31kg].

**Answer:**

An electric field has a magnitude of 400 N/C and makes an angle

60

o

with the perpendicular to the surface of a flat surface of dimensions 30 cm by 20 cm. Calculate the electric flux through the surface.

**Explanation:**

A reconnaissance plane flies 578 km away from

its base at 360 m/s, then flies back to its base

at 540 m/s.

What is its average speed?

Answer in units of m/s.

Considering the definition of speed, the **average speed** is **431.94 m/s**.

Speed is a physical quantity that expresses the **relationship between the space traveled **by an object and** the time** used for it.

In other words, the speed is associated with the change of position of an object in space within a certain amount of time.

The speed can be calculated using the **expression**:

**speed= distance traveled÷ time**

In this case, **you know** that:

**Replacing** in the definition of speed you can calculate the time it takes to fly away and back:

Solving:

Then, the total distance traveled and the total time will be the sum of each of the sections traveled:

**Replacing** in the definition of speed:

speed= 1,156,000 m÷ 2,676.32 s

Solving:

speed= 431.94 m/s

Finally, the **average speed** is **431.94 m/s**.

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Raoul and Maria set out walking from their aunt's house. Raoul walks a certain distance straight east and then a certain distance straight north. A crow passing overhead starts from the same point as Raoul, but flies in a straight line. Raoul observes that the crow flies a total distance of 500 m in a direction 35° north of east to reach the same final point as Raoul. Maria starts from the same point as Raoul, but she walks first straight west and then straight south. Her final point is 700 m from the starting point in a direction that is 55° south of west. How far did Raoul walk on the east leg of his trip? How far on the north leg? Similarly, how far did Maria walk on the west leg and how far on the south leg? Express these quantities in terms of displacement vectors and their components, using a coordinate system with the +x axis pointing east and the +y axis pointing north.

**Answer:**

no entiendo tu pregunta

Which process is a change from gas to liquid?

OA. Freezing

B. Melting

OC. Vaporization

OD. Condensation

**Answer:**

Condensation

**Explanation:**

When water vapour (gas) is cooled it undergoes CONDENSATION to form water(liquid).

An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west. It starts at the 17-inch mark, crawls to the 21-inch mark, then moves to the 8-inch mark. What was the total distance the ant traveled?

The** total distance **that is traveled is **12 inches.**

We know that distance is a **scalar quantity.** The term distance only has to do with the **difference **between two points. The direction is not taken into cognizance when we are discussing the distance that has been covered.

As we have said that distance is a **scalar quantity, **it the follows that the process of obtaining the** total distance** can only be algebraic given that we could directly add all the distance covered by the **ant **in order to obtain the **total distance **of the ant.

Now, we can see that the ant starts at the **17-inch mark**, crawls to the 21-inch mark, then moves to the** 8-inch mark. **The **total distance covered** is obtained from; (21 - 17) + 8 =** 12 inches.**

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Rattlesnake Frequency A timber rattlesnake (Crotalus horridus) shakes its rattle at a characteristic frequency of about 3100 shakes per minuteWhat is this frequency in shakes per second?

**Answer:**

See below

**Explanation:**

31 00 sh / min / 60 s / min = 51 2/3 shakes per second

Average velocity is different than average

speed because calculating average velocity involves

The correct answer is **displacement.**

**Average velocity** differs from average speed because** displacement** is used to calculate **average velocity**.

What is **displacement**?

Being a vector, **displacement** has both magnitude and direction. In one-dimensional motion, the direction should be stated with a plus or minus sign to ensure sure the direction is right. It always occurs in a straight line between two sites. Although it is not a vector variable and lacks a direction sign, the word "distance traveled" is also used to refer to the length of the path that was taken to get from one place to another. The distance traveled is not always equal in both **magnitude and direction**; on occasion, it may exceed the magnitude of the** displacement** between the sites.

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Explain why a car that was driving along a flat surface and is now heading downhill is not in a closed system?

Since an **external force** now acts on the car as it **moves downhill,** it is no longer a** closed system.**

A **closed system **is one in which there is no exchange of energy between the system and the external environment. There is usually a boundary that separates the system from the external environment.

When the car was driving along the flat surface, it could continue moving **endlessly **according to the **Newton's first law** of motion. If the direction is now changed downhill, an **external force **now acts on the car and that is the** force of gravity. **

Since an **external force** now acts on the car as it **moves downhill,** it is no longer a** closed system.**

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a body of mass 7.5kg is moving with the velocity of 1.2, if a force of 15newton is applied to the body calculate its velocity after 2 seconds

The velocity is 5.2 m/s

Force as per the **Newton's second law of motion** is defined as, for constant mass, mass times the acceleration

**F= m x a**

where m is the mass of the body in kilograms and a is the acceleration is m/s^2

Now we know that acceleration is nothing but rate of change of velocity

i.e. ** a= (v -u)/t**

where v is the final velocity

u is the initial velocity

and t is the time frame in which change takes place

Now the data given to us is as follows:

Force F= 15 Newton

initial velocity u =1.2 m/s

t= 2 seconds

We are required to find the final **velocity v **

Now putting the values in the equation,

**F= m (v-u)/t**

15 = 7.5 (v-1.2)/2

30= 7.5v -9

7.5v=39

v=39/7.5= 5.2 m/s

Hence the **velocity** is** 5.2m/s**

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what do you mean by impulse of a force ?

don't spam-

**Answer:**

**Explanation:**

Impulse of a force is defined as the product of the average force and the time interval for which the force acts on the body.

**Answer:**

The product of the force & the time for which it acts on a body is called impulse of a force.

What is the speed of the electron when it is 10.0 cm from the +3.00 nC charge?

The** speed of the electron** when it is 10.0 cm from the +3.00 nC charge is 30×[tex]10^{-2}[/tex] meters per second.

Given :

q=3.00 nC

r=distance=10 c.m

we apply formula

Velocity of electron =qd

=10×[tex]10^{-2}[/tex]×3=30×[tex]10^{-2}[/tex] m/sec

The **speed** of electricity is determined by what you mean by the term "electricity." This is a broad term that essentially means "all things relating to **electric charge.**" I'll presume we're talking about an electrical charge current moving through a metal wire, like the power cord of a light. Electrical currents passing through metal wires have three different velocities, all of which are physically significant:

The velocity of **electron drift.**

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Kalea throws a baseball directly upward at time t = 0 at an initial speed of 14.3 m/s. How high h does the ball rise above its release point? Ignore air resistance and use g = 9.80 m/s^2.

The ball reaches a height of 9.57 meters against **gravity**.

The acceleration an object experiences as a result of gravitational force is known as acceleration due to **gravity**. M/s2 is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on the earth's surface is 9.8 m/s2.

A body is drawn toward the center of the earth by the force of **gravity**. Let's have a look at two bodies with masses ma and mb. When two bodies are subjected to equal forces, the force in terms of mass is given by:

The inertial mass of a body is defined as mb = ma [aA/aB].

In response to the gravitational pull of two bodies,

FA = GMmA/r2,

FB = GMmB/r2,

mB = [FB/FA] × mA

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I need help with this question , thank you

**Answer:**

Should be 400m

**Explanation:**

5.

In 1934, the wind speed on Mt. Washington in New Hampshire reached a record high.

Suppose a very sturdy glider is launched in this wind, so that in 45s the glider reaches the

speed of the wind. If the glider undergoes constant acceleration of 2.29m/s², what is the

wind's speed? Assume the glider is initially at rest.

The **Speed **of wind will be **103.5 m/s**.

It is stated in the question that a glider is launched into the wind and in **45 seconds **it attains the speed of the wind. Also, It is given that it attains a constant acceleration of** 2.29m/s² **and it starts moving from a state of **rest**.

We know the relation between velocity, time, and acceleration can be represented by **Newton's **first equation:** v = u + at**

where, **v **= Final velocity, **u **= Initial velocity, **a **= Acceleration, and **t **= Time

In this case, we have to find the final velocity of the glider to know the speed of the wind, and u = 0, a = 2.29m/s², t = 45sec

Putting values in the equation we get :

=> v = 0 + (2.29)*45

=> **v = 103.5 **

Hence, the **Speed of wind **will be **103.5 m/s**

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While John is traveling along a straight interstate highway, he notices that the mile marker reads 252km. John travels until he reaches the 145km marker and then retraces his path to the 177km marker. What is John's resultant displacement from the 252km marker? Answer in units of km.

John's **resultant displacement** from the 252km marker when traveling along a straight interstate highway is 75 km

**Δx = **[tex]x_{2}[/tex]** - **[tex]x_{1}[/tex]

Δx = Displacement

[tex]x_{2}[/tex] = Final position

[tex]x_{1}[/tex] = Initial position

[tex]x_{2}[/tex] = 177 km

[tex]x_{1}[/tex] = 252 km

Δx = 177 - 252

Δx = - 75 km

Displacement is the **shortest distance** between initial and final positions. It is denoted using Δx. Since, it is a measure of length, its unit is usually meter.

Therefore, John's resultant displacement from the 252km marker when traveling along a straight interstate highway is **-75 km**

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The actual mass of a metal sphere was reported in the manual catalog to be 3.53 kg.

A group of 4 students were assigned to perform an experiment and measure the mass of the sphere each one of them using a different scale or balance.

Student 1 reported 3.6 kg

Student 2 reported 3.5 kg

Student 3 reported 3.12 kg

Student 4 reported 3.476 kg

Which of the four students reported the most precise measurement?

1. Student 1

2. Student 2

3. Student 3

4. Student 4

The **student **that gave the **most precise measurement **is **student 2.**

A **precise measurement **is one that is close together especially when we have a** replicate measurement**. The measurements that are close together are said to be presence. A measurement is accurate when the measurement is **quite close** to the **true value.** Precision ad accuracy are very important in a measurement.

In this case, let us consider the **measurement **of each student;

We can see that the **student **that gave the **most precise measurement **is **student 2.**

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d = 250 g/cm³ V = ? m = 1000 g

The **volume** is **4cm³**.

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A force of 30 N is exerted on a wheeled cart. There is so little friction you can

ignore it. The acceleration of the cart is 6 m/s². Find the mass of the cart.

**Answer:**

force =mass*acceleration due to gravity

mass=force/acceleration

mass =30/6

mass=5kg

Exercise 1 Fill in the blank with the correct personal pronoun. Underline the antecedent for each pronoun.Kristen thought her younger brothers might be frightened when _____________ were close to snakes.
Within the manufacturing industry, there are fourteen subindustries. Which of thefollowing is one of these subindustries?A) Shipping and warehousing.B) Petroleum and coal products.C) Automobile manufacturing.D) Concrete and steel.
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How does variation in molecular units provide cells with a wider range of functions?
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